Cryptography 3
Classical Encryption Techniques:
As we mentioned earlier , the basic of all encryption techniques are based on 2 techniques
1- Substitution
2- Transposition
and we can also use a combination of both of them.
1- Substitution Encryption techniques :
Substitution is an encryption technique which elements in the plaintext are replaced or mapped with another elements.
There are many types of the substitution techniques such as (Monoalphabetic Cipher and Polyalphabetic Cipher)
A- Monoalphabetic Cipher :
we will drive an example of monoalphabetic cipher called (Caesar cipher)
Caesar Cipher :
Is the simplest and the oldest known encryption techniques which elements in the plaintext are shifted with fixed number for example 3 places
Example :
Plaintext : WELCOME TO CRYPTOGRAPHY
Ciphertext : ZHOFRPH WR FUBSWRJUDSKB
The ciphertext is produced by adding 3 position for every letter.
As we can see here the encryption algorithm for each plaintext P, and shifted by 3 places to produces a ciphertext C.
C= E(3,P) = (P+3)mod26
so, generally The encryption algorithm for Caesar cipher is
C= E(K,P) = (P+K)mod26
The decryption algorithm for Caesar cipher is
P= D(K,C) = (C-K)mod26
note : K takes a value from 1 to 25.
Caesar cipher is too easy to break because it's only uses 25 position keys, so simply try to preform a brute force using the 25 possible keys, and the language would help us in breaking this cipher.
Nowadays in modern encryption we uses a very large keys such as 2048 bits or greater key long
that gives us 2^2048 key space, it's a very wide range of possible of keys.
Caesar cipher and many of substitution ciphers can be broken by using frequency of letters analysis.
Frequency of letters analysis:
It is a method to break a cipher encrypted by a substitution techniques.
it is based on the relative of letters can be determined and compared to a standard frequency distribution for a language (English).
As we can see the previous figure , E is the most letter uses in English words by 12.7% , then T by 9.056%
Or look at the next figure
LIVITCSWPIYVEWHEVSRIQMXLEYVEOIEWHRXEXIPFEMVEWHKVSTYLXZIXLIKIIXPIJVSZEYPERRGERIM
WQLMGLMXQERIWGPSRIHMXQEREKIETXMJTPRGEVEKEITREWHEXXLEXXMZITWAWSQWXSWEXTVEPMRXRSJ
GSTVRIEYVIEXCVMUIMWERGMIWXMJMGCSMWXSJOMIQXLIVIQIVIXQSVSTWHKPEGARCSXRWIEVSWIIBXV
IZMXFSJXLIKEGAEWHEPSWYSWIWIEVXLISXLIVXLIRGEPIRQIVIIBGIIHMWYPFLEVHEWHYPSRRFQMXLE
PPXLIECCIEVEWGISJKTVWMRLIHYSPHXLIQIMYLXSJXLIMWRIGXQEROIVFVIZEVAEKPIEWHXEAMWYEPP
XLMWYRMWXSGSWRMHIVEXMSWMGSTPHLEVHPFKPEZINTCMXIVJSVLMRSCMWMSWVIRCIGXMWYMX
It's a classic encryption technique , we try to apply the relative frequency analysis.
letter frequencies :
i : 58
e : 48
x : 41
w : 35
m : 34
v : 31
s : 30
r : 27
l : 22
p : 21
g : 16
h : 16
y : 13
t : 12
q : 12
c : 9
k : 9
j : 9
z : 6
f : 6
a : 5
o : 3
b : 2
u : 1
n : 1
d : 0
With this numbers and with some good guessing some words we can solve it.
let's try I=e and L=H ,let's guessing X=t and E=a and we get the following
heVeTCSWPeYVaWHaVSReQMthaYVaOeaWHRtatePFaMVaWHKVSTYhtZetheKeetPeJVSZaYPaRRGaReM
WQhMGhMtQaReWGPSReHMtQaRaKeaTtMJTPRGaVaKaeTRaWHatthattMZeTWAWSQWtSWatTVaPMRtRSJ
GSTVReaYVeatCVMUeMWaRGMeWtMJMGCSMWtSJOMeQtheVeQeVetQSVSTWHKPaGARCStRWeaVSWeeBtV
eZMtFSJtheKaGAaWHaPSWYSWeWeaVtheStheVtheRGaPeRQeVeeBGeeHMWYPFhaVHaWHYPSRRFQMtha
PPtheaCCeaVaWGeSJKTVWMRheHYSPHtheQeMYhtSJtheMWReGtQaROeVFVeZaVAaKPeaWHtaAMWYaPP
we can substitute V=r in "heVe" to be "here" and R=s in "Rtate" to be "state"
M=i , Z=m from "atthattMZe" to be "atthattime"
we apply this change and get
hereTCSWPeYraWHarSseQithaYraOeaWHstatePFairaWHKrSTYhtmetheKeetPeJrSmaYPassGasei
WQhiGhitQaseWGPSseHitQasaKeaTtiJTPsGaraKaeTsaWHatthattimeTWAWSQWtSWatTraPistsSJ
GSTrseaYreatCriUeiWasGieWtiJiGCSiWtSJOieQthereQeretQSrSTWHKPaGAsCStsWearSWeeBtr
emitFSJtheKaGAaWHaPSWYSWeWeartheStherthesGaPesQereeBGeeHiWYPFharHaWHYPSssFQitha
PPtheaCCearaWGeSJKTrWisheHYSPHtheQeiYhtSJtheiWseGtQasOerFremarAaKPeaWHtaAiWYaPP
thiWYsiWtSGSWsiHeratiSWiGSTPHharHPFKPameNTCiterJSrhisSCiWiSWresCeGtiWYit
We go to deduce the substitution until we get a right message
hereuponlegrandarosewithagraveandstatelyairandbroughtmethebeetlefromaglasscasei
nwhichitwasencloseditwasabeautifulscarabaeusandatthattimeunknowntonaturalistsof
courseagreatprizeinascientificpointofviewthereweretworoundblackspotsnearoneextr
emityofthebackandalongoneneartheotherthescaleswereexceedinglyhardandglossywitha
lltheappearanceofburnishedgoldtheweightoftheinsectwasveryremarkableandtakingall
thingsintoconsiderationicouldhardlyblamejupiterforhisopinionrespectingit
After adding spaces
Hereupon Legrand arose, with a grave and stately air, and brought me the beetle
from a glass case in which it was enclosed. It was a beautiful scarabaeus, and, at
that time, unknown to naturalists—of course a great prize in a scientific point
of view. There were two round black spots near one extremity of the back, and a
long one near the other. The scales were exceedingly hard and glossy, with all the
appearance of burnished gold. The weight of the insect was very remarkable, and,
taking all things into consideration, I could hardly blame Jupiter for his opinion
respecting it.
Note : Frequency of letters analysis works better as long as the cipher text is large.